oracle sql select語句的使用方法
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select格式:

SELECT [ ALL | DISTINCT ] <字段表達式1[,<字段表達式2[,…]

FROM <表名1>,<表名2>[,…]

[WHERE <篩選擇條件表達式>]

[GROUP BY <分組表達式> [HAVING<分組條件表達式>]]

[ORDER BY <字段>[ASC | DESC]]

語句說明:

[]方括號為可選項

[GROUP BY <分組表達式> [HAVING<分組條件表達式>]]

指將結(jié)果按<分組表達式>的值進行分組,該值相等的記錄為一組,帶【HAVING】

短語則只有滿足指定條件的組才會輸出。

[ORDER BY <字段>[ASC | DESC]]

顯示結(jié)果要按<字段>值升序或降序進行排序

練習(xí):

1:表hkb_test_sore取出成績sore前5名的記錄,

2:取第5名的記錄

1,答案select a.sore_id, a.sore

from (select * from hkb_test_sore order by sore desc) a

where rownum <=5

2,答案select a.sore_id, a.sore

from (select * from hkb_test_sore order by sore desc) a

where rownum <=5

minus

select a.sore_id, a.sore

from (select * from hkb_test_sore order by sore desc) a

where rownum <=4;

3:查詢兩個分?jǐn)?shù)一樣的記錄

select *

from hkb_test_sore a

where a.sore = (select sore

from hkb_test_sore a

group by a.sore

having count(a.sore) = 2);

union,union all,intersect,minus的區(qū)別:

SQL> select * from hkb_test2;

X Y

---- -----

a 1

b 2

c 3

g 4

SQL> select * from hkb_test3;

X Y

---- -----

a 1

b 2

e 3

f 4

SQL> select * from hkb_test2;

X Y

---- -----

a 1

b 2

c 3

g 4

SQL> select * from hkb_test3;

X Y

---- -----

a 1

b 2

e 3

f 4

SQL> select * from hkb_test2

2 union

3 select * from hkb_test3;

X Y

---- -----

a 1

b 2

c 3

e 3

f 4

g 4

6 rows selected

SQL> select * from hkb_test2

2 union all

3 select * from hkb_test3;

X Y

---- -----

a 1

b 2

c 3

g 4

a 1

b 2

e 3

f 4

8 rows selected

SQL> select * from hkb_test2

2 intersect

3 select * from hkb_test3;

X Y

---- -----

a 1

b 2

SQL> select * from hkb_test2

2 minus

3 select * from hkb_test3;

X Y

---- -----

c 3

g 4

綜合上面實例看個完整的實例

SQL>

SQL>

SQL> -- create demo table

SQL> create table Employee(

2 ID VARCHAR2(4 BYTE) NOT NULL primary key,

3 First_Name VARCHAR2(10 BYTE),

4 Last_Name VARCHAR2(10 BYTE),

5 Start_Date DATE,

6 End_Date DATE,

7 Salary Number(8,2),

8 City VARCHAR2(10 BYTE),

9 Description VARCHAR2(15 BYTE)

10 )

11 /

Table created.

SQL>

SQL> -- prepare data

SQL> insert into Employee(ID, First_Name, Last_Name, Start_Date, End_Date, Salary, City, Description)

2 values ('01','Jason', 'Martin', to_date('19960725','YYYYMMDD'), to_date('20060725','YYYYMMDD'), 1234.56, 'Toronto', 'Programmer')

3 /

1 row created.

SQL> insert into Employee(ID, First_Name, Last_Name, Start_Date, End_Date, Salary, City, Description)

2 values('02','Alison', 'Mathews', to_date('19760321','YYYYMMDD'), to_date('19860221','YYYYMMDD'), 6661.78, 'Vancouver','Tester')

3 /

1 row created.

SQL> insert into Employee(ID, First_Name, Last_Name, Start_Date, End_Date, Salary, City, Description)

2 values('03','James', 'Smith', to_date('19781212','YYYYMMDD'), to_date('19900315','YYYYMMDD'), 6544.78, 'Vancouver','Tester')

3 /

1 row created.

SQL> insert into Employee(ID, First_Name, Last_Name, Start_Date, End_Date, Salary, City, Description)

2 values('04','Celia', 'Rice', to_date('19821024','YYYYMMDD'), to_date('19990421','YYYYMMDD'), 2344.78, 'Vancouver','Manager')

3 /

1 row created.

SQL> insert into Employee(ID, First_Name, Last_Name, Start_Date, End_Date, Salary, City, Description)

2 values('05','Robert', 'Black', to_date('19840115','YYYYMMDD'), to_date('19980808','YYYYMMDD'), 2334.78, 'Vancouver','Tester')

3 /

1 row created.

SQL> insert into Employee(ID, First_Name, Last_Name, Start_Date, End_Date, Salary, City, Description)

2 values('06','Linda', 'Green', to_date('19870730','YYYYMMDD'), to_date('19960104','YYYYMMDD'), 4322.78,'New York', 'Tester')

3 /

1 row created.

SQL> insert into Employee(ID, First_Name, Last_Name, Start_Date, End_Date, Salary, City, Description)

2 values('07','David', 'Larry', to_date('19901231','YYYYMMDD'), to_date('19980212','YYYYMMDD'), 7897.78,'New York', 'Manager')

3 /

1 row created.

SQL> insert into Employee(ID, First_Name, Last_Name, Start_Date, End_Date, Salary, City, Description)

2 values('08','James', 'Cat', to_date('19960917','YYYYMMDD'), to_date('20020415','YYYYMMDD'), 1232.78,'Vancouver', 'Tester')

3 /

1 row created.

SQL>

SQL>

SQL>

SQL> -- display data in the table

SQL> select * from Employee

2 /

ID FIRST_NAME LAST_NAME START_DAT END_DATE SALARY CITY DESCRIPTION

---- -------------------- -------------------- --------- --------- ---------- ---------- ---------------

01 Jason Martin 25-JUL-96 25-JUL-06 1234.56 Toronto Programmer

02 Alison Mathews 21-MAR-76 21-FEB-86 6661.78 Vancouver Tester

03 James Smith 12-DEC-78 15-MAR-90 6544.78 Vancouver Tester

04 Celia Rice 24-OCT-82 21-APR-99 2344.78 Vancouver Manager

05 Robert Black 15-JAN-84 08-AUG-98 2334.78 Vancouver Tester

06 Linda Green 30-JUL-87 04-JAN-96 4322.78 New York Tester

07 David Larry 31-DEC-90 12-FEB-98 7897.78 New York Manager

08 James Cat 17-SEP-96 15-APR-02 1232.78 Vancouver Tester

8 rows selected.

SQL>

SQL>

SQL> SELECT id, first_name, last_name FROM employee

2 /

ID FIRST_NAME LAST_NAME

---- -------------------- --------------------

01 Jason Martin

02 Alison Mathews

03 James Smith

04 Celia Rice

05 Robert Black

06 Linda Green

07 David Larry

08 James Cat

8 rows selected.

在ORACLE中實現(xiàn)SELECT TOP N的方法

1.在ORACLE中實現(xiàn)SELECT TOP N

由于ORACLE不支持SELECT TOP語句,所以在ORACLE中經(jīng)常是用ORDER BY跟ROWNUM的組合來實現(xiàn)SELECT TOP N的查詢。

簡單地說,實現(xiàn)方法如下所示:

SELECT 列名1...列名n FROM

(SELECT 列名1...列名n FROM 表名 ORDER BY 列名1...列名n)

WHERE ROWNUM <= N(抽出記錄數(shù))

ORDER BY ROWNUM ASC

下面舉個例子簡單說明一下。

顧客表customer(id,name)有如下數(shù)據(jù):

ID NAME

01 first

02 Second

03 third

04 forth

05 fifth

06 sixth

07 seventh

08 eighth

09 ninth

10 tenth

11 last

則按NAME的字母順抽出前三個顧客的SQL語句如下所示:

SELECT * FROM

(SELECT * FROM CUSTOMER ORDER BY NAME)

WHERE ROWNUM <= 3

ORDER BY ROWNUM ASC

輸出結(jié)果為:

ID NAME

08 eighth

05 fifth

01 first

2.在TOP N紀(jì)錄中抽出第M(M <= N)條記錄

在得到了TOP N的數(shù)據(jù)之后,為了抽出這N條記錄中的第M條記錄,我們可以考慮從ROWNUM著手。我們知道,ROWNUM是記錄表中數(shù)據(jù)編號的一個隱藏子段,所以可以在得到TOP N條記錄的時候同時抽出記錄的ROWNUM,然后再從這N條記錄中抽取記錄編號為M的記錄,即使我們希望得到的結(jié)果。

從上面的分析可以很容易得到下面的SQL語句。

SELECT 列名1...列名n FROM

(

SELECT ROWNUM RECNO, 列名1...列名nFROM

(SELECT 列名1...列名n FROM 表名 ORDER BY 列名1...列名n)

WHERE ROWNUM <= N(抽出記錄數(shù))

ORDER BY ROWNUM ASC

)

WHERE RECNO = M(M <= N)

同樣以上表的數(shù)據(jù)為基礎(chǔ),那么得到以NAME的字母順排序的第二個顧客的信息的SQL語句應(yīng)該這樣寫:

SELECT ID, NAME FROM

(

SELECT ROWNUM RECNO, ID, NAME FROM

(SELECT * FROM CUSTOMER ORDER BY NAME)

WHERE ROWNUM <= 3

ORDER BY ROWNUM ASC )

WHERE RECNO = 2

結(jié)果則為:

ID NAME

05 fifth

3.抽出按某種方式排序的記錄集中的第N條記錄

在2的說明中,當(dāng)M = N的時候,即為我們的標(biāo)題講的結(jié)果。實際上,2的做法在里面N>M的部分的數(shù)據(jù)是基本上不會用到的,我們僅僅是為了說明方便而采用。

如上所述,則SQL語句應(yīng)為:

SELECT 列名1...列名n FROM

(

SELECT ROWNUM RECNO, 列名1...列名nFROM

(SELECT 列名1...列名n FROM 表名 ORDER BY 列名1...列名n)

WHERE ROWNUM <= N(抽出記錄數(shù))

ORDER BY ROWNUM ASC

)

WHERE RECNO = N

那么,2中的例子的SQL語句則為:

SELECT ID, NAME FROM

(

SELECT ROWNUM RECNO, ID, NAME FROM

(SELECT * FROM CUSTOMER ORDER BY NAME)

WHERE ROWNUM <= 2

ORDER BY ROWNUM ASC

)

WHERE RECNO = 2

結(jié)果為:

ID NAME

05 fifth

4.抽出按某種方式排序的記錄集中的第M條記錄開始的X條記錄

3里所講得僅僅是抽取一條記錄的情況,當(dāng)我們需要抽取多條記錄的時候,此時在2中的N的取值應(yīng)該是在N >= (M + X - 1)這個范圍內(nèi),當(dāng)讓最經(jīng)濟的取值就是取等好的時候了的時候了。當(dāng)然最后的抽取條件也不是RECNO = N了,應(yīng)該是RECNO BETWEEN M AND (M + X - 1)了,所以隨之而來的SQL語句則為:

SELECT 列名1...列名n FROM

(

SELECT ROWNUM RECNO, 列名1...列名nFROM

(

SELECT 列名1...列名n FROM 表名 ORDER BY 列名1...列名n)

WHERE ROWNUM <= N (N >= (M + X - 1))

ORDER BY ROWNUM ASC

)

WHERE RECNO BETWEEN M AND (M + X - 1)

同樣以上面的數(shù)據(jù)為例,則抽取NAME的字母順的第2條記錄開始的3條記錄的SQL語句為:

SELECT ID, NAME FROM

(

SELECT ROWNUM RECNO, ID, NAME FROM

(SELECT * FROM CUSTOMER ORDER BY NAME)

WHERE ROWNUM <= (2 + 3 - 1)

ORDER BY ROWNUM ASC

)

WHERE RECNO BETWEEN 2 AND (2 + 3 - 1)

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